B in A B
Crossword Clue

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AnswerCrossword Clue
ADDENDB, in A + B.
DRJN.B.A. star who started in the A.B.A.
limacona plane curve whose equation in polar coordinates has one of the forms ? = a cos ? ▒ b or ? = a sin ? ▒ b and which reduces to a cardioid when a = b
transitive(of a relation) Such that, if it applies between successive members of a sequence, it must also apply between any two members taken in order. For instance, if A is larger than B, and B is larger than C, then A is larger than C
BENEThe "b" in n. b.
BENEThe B in N. B.
BENEThe "B" in N.B.
BATTEDThe "B" in R. B. I.
BAKERThe "B" in Ivy B. Priest.
BEECHERThe B in H. B. Stowe.
BERNARDThe "B" in G.B.S.
BAINESThe "B" in L.B.J.
BAINESThe B in L.B.J.
INITThe G, W or B in G.W.B.
SITINB.B. King "I'm Gonna ... 'Til You Give In"
DEGREESB.A. and B.S.
DEGA.B. or B.A.
DEGREESA. B. and B. S.
STATB.A. or R.B.I.
DEGB.A. or M.B.A.
DEGB.S. or M.B.A.
BRANDYPart of a B and B
BOYThe "B" of B.S.A.
DEGSB.A. and B.S., e.g.
ORGSA.A.A. and B.B.B.
EARSC.B. equipment, to a C.B.'er
THEDRILLISGONEB.B. King song about a missing tool?
ORGSA.A.A. and B.B.B., e.g.
abelianhaving the property a x b = b x a
ERVINGHoops star during the N.B.A.-A.B.A. merger
contrapositionsConversion of a proposition from all A is B to all not-B is not-A
contrapositionConversion of a proposition from all A is B to all not-B is not-A
commutativeInvolving the condition that a group of quantities connected by operators gives the same result whatever the order of the quantities involved, e.g., a Î b = b Î a
ascendera. the part of a lowercase letter, as b, d, f, h, that rises above x-height b. letter rising above x-height, as b, d, f, h, etc.
jomonof, relating to, or typical of a Japanese cultural period from about the fifth or fourth millennium b.c. to about 200 b.c. and characterized by elaborately ornamented hand-formed unglazed pottery
associativeInvolving the condition that a group of quantities connected by operators gives the same result whatever their grouping, as long as their order remains the same, e.g., (a Î b) Î c = a Î (b Î c)
BLUESMANKINGB B
INNB and B
BETASB and B?
BETASB and b